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In his new video, Talwalkaris asked a question from the 1876 algebra test presented to participants at the Massachusetts Institute of Technology.
Talwalkaris urges his channel fans to check how well they would have done before standardized tests.
The question is simple:
“The father told the son: ‘Two years ago I was three times older than you; But in fourteen years I’ll only be twice as old as you. “How old are they now?”
Try to fix this problem. You can find the solution below.
You can watch a video explaining the answer by clicking this link.
As Talwalkaris explains, the solution is quite simple, expressed by an equation f – 2 = 3 (s – 2) f – 2 = 3 (s – 2), when F and s denotes the age of the father and son, respectively.
Let’s take the second part: if after 14 years the father will be only twice as old as the son, his age can be expressed by the equation f + 14 = 2 (s + 14) f + 14 = 2 (s + 14), when F and s it still marks the age of father and son.
Now there is a system of two equations and two unknowns:
f + 14 = 2s + 28f + 14 = 2s + 28f – 2 = 3s – 6f – 2 = 3s – 6
With some simple transformations described above, Talwalkar subtracted the second equation from the first and received the answer: an 18-year-old son and a 50-year-old father.
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