Zelensky congratulates Sanda on winning the presidential elections in Moldova / GORDON



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Congratulating former Moldovan Prime Minister Maia Sandu on his victory in the presidential elections, Ukraine’s President Volodymyr Zelenskyy expressed his hope to strengthen relations between the countries.

November 16, Ukraine’s President Volodymyr Zelensky on Twitter congratulated the former Prime Minister of Moldova Maia Sandu with the victory in the presidential elections in Moldova.

“I congratulate Maia Sanda on her victory in the presidential elections in Moldova. I hope to further strengthen relations between Ukraine and Moldova for the European future of our peoples,” wrote the Ukrainian head of state.



Zelensky also called Sandu and wished him success in his work, the Office of the President said.

He assured his colleague that he is ready to continue the close and mutually beneficial cooperation between Ukraine and Moldova, established, among other things, during Maia Sandu’s visit to Kiev as Prime Minister of the Republic of Moldova in July 2019. Volodymyr Zelenskyy noted that Ukraine is committed to the implementation of new ambitious projects. , mainly infrastructure and aimed at promoting the European integration of the two countries, “he said in the message.

Zelensky also thanked Sanda for her constant support for Ukraine’s sovereignty and territorial integrity and invited her to Kiev on an official visit.

“Interlocutors also discussed the problems of the COVID-19 pandemic and expressed the hope that humanity can confront it in the short term, and our countries – with its tangible consequences, mainly economic,” noted the Office of the President of Ukraine.

On November 15, the second round of the presidential elections took place in Moldova; Sandu and the current president of Moldova, Igor Dodon, ran for office. The data from the CEC of Moldova testify to the victory of the former prime minister: after counting 99.95% of the votes, Sandu’s result is 57.74%.



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