Russia sent eight fighters to intercept three American B-52 bombers near Crimea

The Russian Defense Ministry announced on September 4 that it had sent eight fighters after Moscow discovered three American B-52 bombers flying over the Black Sea area near the Crimean peninsula.

“To prevent US Air Force planes from violating Russian airspace, 4 Su-27 fighters and 4 Su-30 fighters of the Southern Air Force were sent to the Black Sea and the Sea of ​​Azov. “Said the Defense Management Center of the Russian Federation.

The announcement states that Russian fighters quickly escorted American planes out of Russian airspace. “US aircraft violating the Russian federal border are not allowed,” the announcement concluded.

Earlier, on August 28, Russia also sent two Su-27s to intercept several B-52s over the Black Sea. A day later, a similar incident occurred in the Baltic Sea and again involved B-52.

According to the SputnikThe August 28 incident is seen as an unprecedented demonstration of US military capabilities as the country sent six B-52s to fly to 30 NATO member countries in just one day.

The September 4 incident took place against the background of the US Army starting live fire drills in Estonia, some 112 km from the Russian border.

According to the RTWhen three B-52s flew near Crimea yesterday, British and American intelligence gathering ships and aircraft appeared in Ukrainian airspace and over the Black Sea. This seems to indicate that the B-52s may have carried out a test mission for the Russian air defense and radar system in Crimea.

Also, RT He thought this could be a move to show America’s military strength close to Russia.

In a press release from the United States European Command, this unit said that three B-52 bombers coordinated with Ukrainian fighters for “air training” and the incident demonstrated the capabilities of the United States and NATO in “against Russia and provide assurances to allies and partners “.

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According to the RT, Sputnik