[ad_1]
Raheem Sterling has joined the elite after becoming the third player, after Lionel Messi and Sergio Agüero, who has scored at least 100 goals with Pep Guardiola.
The 26-year-old reached the milestone in Manchester City’s emphatic 4-1 win over Liverpool at Anfield after returning home from virtually the finish line following Alisson’s second major mistake in the competition.
Sterling’s first with the Spaniard came when he scored the first goal in a 3-1 win over West Ham at the Etihad in August 2016, and has since become one of the most prolific finalists in Europe, with 90 goals. for the Premier League giants from the start of the 2017-18 season.
Aguero joined the 100 club after scoring his first of a double against Brighton in August 2019 and since then the Argentine has managed 20 more despite significant spells on the sidelines.
Naturally, Messi was the first to reach a century of goals with Guardiola and is in a league of his own after he became arguably the most complete player of all time.
The Messi-Guardiola partnership lasted just four years, but saw Barcelona’s top scorer score an astonishing 211 goals, including 73 in Guardiola’s last season at the club in 2011-12.
If Sterling wants to emulate Messi’s achievement, he needs to stay at Etihad for a while.
On a day when City consolidated at the top of the Premier League, more individual and team records were equaled, broken or extended.
Guardiola’s team has joined Preston and Arsenal to become the only top-flight English teams to win 14 matches in a row.
Phil Foden also became the youngest opponent to score and assist in the same Premier League game at Anfield, while Ilkay Gundogan’s reinvention as a scoring midfielder continues as the German added two more goals to his account on Sunday. late to score seven league goals in 2021, three more than any other player.
City’s chance to turn their 15th consecutive win into a record will come Saturday when they host Tottenham. Guardiola’s men sport unstoppable strength right now.
Source: m.allfootballapp.com
[ad_2]
